{"id":18208,"date":"2024-04-02T14:24:32","date_gmt":"2024-04-02T14:24:32","guid":{"rendered":"https:\/\/soicau3069.minhngocxoso.com\/?p=18208"},"modified":"2024-04-02T14:24:32","modified_gmt":"2024-04-02T14:24:32","slug":"chi-tiet-cac-cach-bat-tong-dac-biet-chuan-xac-nhat","status":"publish","type":"post","link":"https:\/\/losieudep.com\/chi-tiet-cac-cach-bat-tong-dac-biet-chuan-xac-nhat\/","title":{"rendered":"chi ti\u1ebft c\u00e1c c\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t chu\u1ea9n x\u00e1c nh\u1ea5t"},"content":{"rendered":"
C\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t l\u00e0 ph\u01b0\u01a1ng ph\u00e1p \u0111\u01b0\u1ee3c r\u1ea5t nhi\u1ec1u ng\u01b0\u1eddi \u01b0a chu\u1ed9ng b\u1edfi t\u00ednh \u1ee9ng d\u1ee5ng c\u1ee7a n\u00f3. Tuy v\u1eady l\u1ea1i \u00edt ng\u01b0\u1eddi ng\u01b0\u1eddi th\u00e0nh th\u1ea1o. C\u00f9ng t\u00ecm hi\u1ec3u chi ti\u1ebft v\u1ec1 c\u00e1ch n\u00e0y nh\u00e9. N\u1ebfu b\u1ea1n \u00e1p d\u1ee5ng chu\u1ea9n soi t\u1ed5ng \u0111\u1ec1 MB n\u00e0y \u0111\u1ea3m b\u1ea3o c\u00f3 t\u1ec9 l\u1ec7 tr\u00fang r\u1ea5t cao nh\u00e9.<\/p>\n
\u0110\u1ea7u ti\u00ean ta c\u1ea7n hi\u1ec3u s\u01a1 qua t\u1ed5ng \u0111\u1ec1 l\u00e0 k\u1ebft qu\u1ea3 khi ta c\u1ed9ng 2 s\u1ed1 cu\u1ed1i trong gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u1edbi nhau theo ki\u1ec3u t\u00ednh b\u00e0i 3 c\u00e2y<\/p>\n
VD: \u0110\u1ec1 v\u1ec1 81 th\u00ec t\u1ed5ng \u0111\u1ec1 l\u00e0 1+8=9, c\u00f2n n\u1ebfu \u0111\u1ec1 v\u1ec1 83 th\u00ec t\u00ednh nh\u01b0 nhau 8+3=11. Ta c\u00f3 t\u1ed5ng \u0111\u1ec1 l\u00e0 1 do 11-10=1<\/p>\n
L\u00e0 ph\u01b0\u01a1ng ph\u00e1p d\u1ef1 \u0111o\u00e1n kh\u00e1 chu\u1ea9n v\u00e0 \u0111\u01b0\u1ee3c r\u1ea5t nhi\u1ec1u ng\u01b0\u1eddi ch\u01a1i \u00e1p d\u1ee5ng. Do n\u1ebfu b\u1eaft theo k\u1ebft qu\u1ea3 n\u00e0y th\u01b0\u1eddng r\u1ea5t ch\u00ednh x\u00e1c v\u00e0 r\u1ea5t \u00edt b\u1ecb sai. V\u00ec v\u1eady, khuy\u1ebfn kh\u00edch ng\u01b0\u1eddi m\u1edbi tham gia \u0111\u1ec3 \u0111\u00e1nh theo \u0111\u1ea3m b\u1ea3o t\u1ef7 l\u1ec7 th\u1eafng cao.<\/p>\n
Ta ch\u1ec9 c\u1ea7n quan t\u00e2m \u0111\u1ebfn k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 ng\u00e0y th\u1ee9 2 m\u1ed7i tu\u1ea7n.<\/p>\n
V\u00e0 \u1edf b\u1ea3ng k\u1ebft qu\u1ea3 s\u1ed1 ng\u00e0y th\u1ee9 2 s\u1ebd d\u00f9ng 2 s\u1ed1 \u0111\u1ea7u c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t l\u00e0m t\u1ed5ng \u0111\u1ec1. T\u1eeb \u0111\u00f3, \u0111\u1ee3i \u0111\u1ebfn th\u1ee9 4 ho\u1eb7c th\u1ee9 5 v\u00e0 \u0111\u00e1nh li\u00ean t\u1ee5c \u0111\u1ebfn h\u1ebft tu\u1ea7n.<\/p>\n
VD: N\u1ebfu k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t c\u1ee7a ng\u00e0y 4\/11 l\u00e0 0 + 5 + 4 + 7 + 3, t\u1ed5ng c\u1ee7a gi\u1ea3i n\u00e0y l\u00e0 1. Theo \u0111\u00f3 c\u00e1c b\u1ea1n n\u00ean ch\u1ecdn nh\u1eefng con l\u00f4 c\u00f3 t\u1ed5ng 2 ch\u1eef s\u1ed1 b\u1eb1ng 1 \u0111\u1ec3 ch\u01a1i cho tu\u1ea7n sau. S\u1ebd c\u00f3 10 con s\u1ed1 bao g\u1ed3m: 01 \u2013 29 \u2013 92 \u2013 38 \u2013 83 \u2013 47 \u2013 74 \u2013 56 \u2013 65.<\/p>\n
V\u1edbi c\u00e1ch s\u1eed d\u1ee5ng \u0111\u1ec3 b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t. V\u1edbi nh\u1eefng ng\u01b0\u1eddi ch\u01a1i kinh nghi\u1ec7m th\u00ec t\u00ecm ra quy lu\u1eadt r\u1ea5t d\u1ec5. Ch\u1ec9 c\u1ea7n b\u1ea1n c\u1ed9ng t\u1ea5t c\u1ea3 5 s\u1ed1 trong gi\u1ea3i \u0111\u1eb7c bi\u1ec7t th\u00e0nh 1 s\u1ed1 v\u00e0 l\u1ea5y s\u1ed1 \u0111\u00f3 \u0111\u00e1nh cho ng\u00e0y ti\u1ebfp theo. Ta ch\u1ec9 \u0111\u00e1nh 1 l\u1ea7n ch\u1ee9 kh\u00f4ng nu\u00f4i nh\u00e9<\/p>\n
Ho\u1eb7c l\u00e0 ta c\u1ed9ng t\u1ed5ng gi\u1ea3i \u0111\u1eb7c bi\u1ec7t x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc c\u1ee7a ch\u1ee7 nh\u1eadt tu\u1ea7n n\u00e0y v\u00e0 ti\u1ebfn h\u00e0nh nu\u00f4i trong tu\u1ea7n ti\u1ebfp theo. S\u1ed1 l\u00f4 n\u00e0y c\u00f3 nhi\u1ec1u c\u01a1 h\u1ed9i s\u1ebd v\u1ec1 ng\u00e0y th\u1ee9 3, th\u1ee9 4 trong tu\u1ea7n t\u1edbi.<\/p>\n
B\u1ea1c nh\u1edb l\u00e0 c\u00e1ch truy\u1ec1n th\u1ed1ng trong l\u00f4 \u0111\u1ec1 v\u00e0 trong t\u1ed5ng \u0111\u1ec1 c\u0169ng v\u1eady. \u0110\u00e2y c\u0169ng l\u00e0 ph\u01b0\u01a1ng ph\u00e1p \u0111\u00e1nh gi\u00e1 l\u00e0 c\u00f3 s\u1ef1 an to\u00e0n v\u00e0 hi\u1ec7u qu\u1ea3 cao.<\/p>\n
N\u1ebfu t\u1ed5ng \u0111\u1eb7c bi\u1ec7t r\u01a1i v\u00e0o c\u00e1c tr\u01b0\u1eddng h\u1ee3p \u0111\u1eb7c bi\u1ec7t d\u01b0\u1edbi \u0111\u00e2y th\u00ec ta c\u00f3 th\u1ec3 nghi\u00ean c\u1ee9u nh\u1eefng t\u1ed5ng sau \u0111\u1ec3 \u0111\u00e1nh:<\/p>\n
N\u1ebfu t\u1ed5ng gi\u1ea3i \u0111\u1eb7c bi\u1ec7t KQXS mi\u1ec1n B\u1eafc l\u00e0 9 th\u00ec h\u00f4m sau gi\u1ea3i \u0111\u1eb7c bi\u1ec7t x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc d\u1ec5 v\u1ec1 t\u1ed5ng 5<\/p>\n
N\u1ebfu t\u1ed5ng gi\u1ea3i \u0111\u1eb7c bi\u1ec7t KQXS mi\u1ec1n B\u1eafc l\u00e0 10 th\u00ec h\u00f4m sau gi\u1ea3i \u0111\u1eb7c bi\u1ec7t x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc d\u1ec5 v\u1ec1 t\u1ed5ng 1<\/p>\n
N\u1ebfu t\u1ed5ng gi\u1ea3i \u0111\u1eb7c bi\u1ec7t KQXS mi\u1ec1n B\u1eafc l\u00e0 6 th\u00ec h\u00f4m sau gi\u1ea3i \u0111\u1eb7c bi\u1ec7t x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc d\u1ec5 v\u1ec1 t\u1ed5ng 8<\/p>\n
Tuy nhi\u00ean, nu\u00f4i t\u1ed5ng \u0111\u1ec1 g\u1ed3m nhi\u1ec1u s\u1ed1. Do \u0111\u00f3, n\u1ebfu nu\u00f4i trong th\u1eddi gian d\u00e0i s\u1ebd kh\u00f4ng mang l\u1ea1i hi\u1ec7u qu\u1ea3. Ta ch\u1ec9 n\u00ean nu\u00f4i khung t\u1ed1i \u0111a 3 ng\u00e0y th\u00f4i nh\u00e9<\/p>\n
V\u00ed d\u1ee5: N\u1ebfu t\u1ed5ng c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t ng\u00e0y h\u00f4m nay v\u1ec1 l\u00e0 10 th\u00ec \u0111\u1ec1 ng\u00e0y h\u00f4m sau s\u1ebd n\u1ed5 \u1edf t\u1ed5ng 1. C\u00e1c con s\u1ed1 m\u00e0 anh em n\u00ean nu\u00f4i \u0111\u00e1nh s\u1ebd l\u00e0 01 \u2013 29 \u2013 92 \u2013 38 \u2013 83 \u2013 47 \u2013 74 \u2013 56 \u2013 65.<\/p>\n
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Ta s\u1ebd theo d\u00f5i th\u1ea5y nh\u1eefng th\u00e1ng g\u1ea7n \u0111\u00e2y th\u00ec th\u1ea5y t\u1ed5ng \u0111\u1ec1 li\u00ean t\u1ee5c l\u1eb7p \u0111i l\u1eb7p l\u1ea1i. Th\u1ed1ng k\u00ea k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 m\u1ed7i ng\u00e0y c\u0169ng ch\u01a1i th\u1ea5y vi\u1ec7c m\u1ed9t t\u1ed5ng \u0111\u1ec1 v\u1ec1 li\u00ean t\u1ee5c l\u00e0 r\u1ea5t nhi\u1ec1u. N\u1ebfu ph\u00e2n t\u00edch k\u1ef9 v\u00e0 k\u1ebft h\u1ee3p c\u00f9ng c\u00e1c c\u00e1ch b\u1eaft \u0111\u1ec1 kh\u00e1c t\u1eeb \u0111\u00f3 nu\u00f4i khung s\u1ebd \u0111\u1ea1t l\u00e3i t\u1ed1i \u01b0u nh\u1ea5t<\/p>\n
C\u00e1ch n\u00e0y \u0111\u01b0\u1ee3c hi\u1ec3u \u0111\u01a1n gi\u1ea3n l\u00e0 d\u00f9ng 2 t\u1ed5ng \u0111\u1ec1 \u0111\u1ec3 nu\u00f4i quanh n\u0103m. L\u00e0 c\u00e1ch ch\u01a1i kh\u00e1 ph\u1ed5 bi\u1ebfn c\u1ee7a nh\u1eefng ng\u01b0\u1eddi ch\u01a1i l\u00e2u n\u0103m. C\u1ee5 th\u1ec3, t\u1ed5ng m\u00e0 ta n\u00ean nu\u00f4i trong nh\u1eefng ng\u00e0y 1 \u2013 6 \u0111\u1ea7u m\u1ed7i th\u00e1ng l\u00e0 2 v\u00e0 7.<\/p>\n
L\u01b0u \u00fd, n\u1ebfu m\u1ed9t trong 2 t\u1ed5ng \u0111\u00e3 n\u1ed5 v\u00e0o c\u00e1c ng\u00e0y t\u1eeb 1 \u2013 6 \u0111\u1ea7u th\u00e1ng th\u00ec ta kh\u00f4ng n\u00ean nu\u00f4i l\u1ea1i n\u1eefa. Ngh\u1ec9 1 \u2013 2 th\u00e1ng m\u1edbi b\u1eaft \u0111\u1ea7u ch\u01a1i ti\u1ebfp.<\/p>\n
C\u00e1ch n\u00e0y c\u00f3 th\u1ec3 \u00e1p d\u1ee5ng v\u1edbi nu\u00f4i khung t\u1eeb 3 \u0111\u1ebfn 5 ng\u00e0y. Ph\u01b0\u01a1ng ph\u00e1p n\u00e0y d\u1ef1a tr\u00ean s\u1ed1 th\u1ee9 2 c\u1ee7a gi\u1ea3i 7 l\u00e0m s\u1ed1 t\u1ed5ng \u0111\u1ec1 cho ng\u00e0y ti\u1ebfp theo<\/p>\n
VD: s\u1ed1 th\u1ee9 2 c\u1ee7a gi\u1ea3i 7 v\u1ec1 l\u00e0 56. T\u00ednh t\u1ed5ng s\u1ebd l\u00e0 5+ 6 = 11. Nh\u01b0 v\u1eady s\u1ebd d\u00f9ng t\u1ed5ng 1 \u0111\u1ec3 nu\u00f4i trong 3 \u2013 5 ng\u00e0y t\u1edbi. T\u1ee9c l\u00e0 nu\u00f4i khung d\u00e0n \u0111\u1ec1 01 \u2013 29 \u2013 92 \u2013 38 \u2013 83 \u2013 47 \u2013 74 \u2013 56.<\/p>\n
C\u00e1ch n\u00e0y \u00e1p d\u1ee5ng cho m\u1ecdi c\u1ea7u l\u00f4 mi\u1ec1n B\u1eafc, Trung v\u00e0 Nam.Ta s\u1ebd gh\u00e9p c\u00e1c con s\u1ed1 c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u00e0 gi\u1ea3i nh\u00ec c\u1ee7a c\u00f9ng m\u1ed9t b\u1ea3ng k\u1ebft qu\u1ea3 l\u1ea1i v\u1edbi nhau. Nh\u01b0ng khi ta \u0103n kho\u1ea3ng 3- 4 tu\u1ea7n th\u00ec ngh\u1ec9 1 \u2013 2 tu\u1ea7n r\u1ed3i b\u1ea1n m\u1edbi n\u00ean l\u1ea1i ch\u01a1i ti\u1ebfp.<\/p>\n
Lo\u1ea1i n\u00e0y c\u00f3 c\u00e1ch \u0111\u00e1nh nh\u01b0 sau: B\u1ea1n c\u00f3 th\u1ec3 gh\u00e9p c\u00e1c con s\u1ed1 c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u00e0 gi\u1ea3i nh\u00ec c\u1ee7a c\u00f9ng m\u1ed9t b\u1ea3ng v\u1edbi nhau l\u1ea1i.<\/p>\n
VD: Ta c\u00f3 m\u1ed9t d\u00e3y s\u1ed1 g\u1ed3m 9 con s\u1ed1: 215649897. H\u00e3y c\u1ed9ng d\u1ed3n 2 s\u1ed1 c\u1ea1nh nhau theo quy lu\u1eadt pascal \u0111\u1ebfn khi ch\u1ec9 c\u00f2n 2 ch\u1eef s\u1ed1. Ng\u01b0\u1eddi ch\u01a1i l\u00fac n\u00e0y l\u1ea5y 2 s\u1ed1 cu\u1ed1i c\u00f9ng l\u00e0m c\u1ea7u b\u1ea1ch th\u1ee7 ch\u1ed1t cho ng\u00e0y \u0111\u00f3.<\/p>\n
L\u01b0u \u00fd: Ta n\u00ean b\u1ecdc l\u00f3t con l\u1ed9n ng\u01b0\u1ee3c c\u1ee7a b\u1ea1ch th\u1ee7 l\u00f4 v\u1edbi n\u1eeda v\u1ed1n \u0111\u1ec3 tr\u00e1nh t\u1ea1ch l\u1ed7 qu\u00e1 nhi\u1ec1u. Anh em \u0111\u00e1nh l\u00f4 \u0111\u1ec1 c\u0169ng n\u00ean ch\u00fa \u00fd n\u1ebfu t\u1ed5ng 2 s\u1ed1 li\u1ec1n k\u1ec1 l\u1edbn h\u01a1n 10 ta s\u1ebd l\u1ea5y m\u1ed7i s\u1ed1 \u1edf h\u00e0ng \u0111\u01a1n v\u1ecb<\/p>\n
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C\u00e1ch \u0111\u00e1nh l\u00f4 n\u00e0y \u0111\u01b0\u1ee3c t\u00ednh to\u00e1n nh\u01b0 sau: \u0111\u1ea7u ti\u00ean b\u1ea1n n\u00ean x\u00e1c \u0111\u1ecbnh ng\u00e0y b\u1eaft \u0111\u1ea7u ta t\u00ednh: coi \u0111\u1ec1 ng\u00e0y th\u1ee9 nh\u1ea5t l\u00e0 A, B ng\u00e0y th\u1ee9 2 l\u00e0 C, D.<\/p>\n
Ta c\u00f3 tr\u01b0\u1eddng h\u1ee3p: A+ B= E; C+D=F;<\/p>\n
Ta s\u1ebd c\u00f3 2 tr\u01b0\u1eddng h\u1ee3p<\/p>\n
Tr\u01b0\u1eddng h\u1ee3p 1: N\u1ebfu nh\u01b0 E<10, F< 10 th\u00ec ta n\u00ean l\u1ea5y 10 \u2013 E = X, 10 \u2013 F = Y. \u0110\u00e1nh XY cho l\u00f4 ng\u00e0y th\u1ee9 3.<\/p>\n
Tr\u01b0\u1eddng h\u1ee3p 2: N\u1ebfu t\u1ef7 l\u1ec7 E > 10, F < 10 th\u00ec b\u1ea1n n\u00ean l\u1ea5y 20 \u2013 E = X, 10 \u2013 F= Y, th\u00ec \u0111\u00e1nh l\u00f4 XY ng\u00e0y th\u1ee9 3.<\/p>\n
C\u00e1ch n\u00e0y ta s\u1ebd l\u1ea5y 2 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t c\u1ee7a 2 ng\u00e0y li\u00ean ti\u1ebfp nhau \u0111\u1ec3 t\u00ednh. C\u00f4ng th\u1ee9c nh\u01b0 sau:<\/p>\n
C\u1ed9ng t\u1ea5t c\u1ea3 con s\u1ed1 c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t ng\u00e0y th\u1ee9 nh\u1ea5t ta \u0111\u01b0\u1ee3c 1 con s\u1ed1 l\u00e0 AB.<\/p>\n
C\u1ed9ng t\u1ea5t c\u1ea3 con s\u1ed1 c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t ng\u00e0y th\u1ee9 nh\u1ea5t ta \u0111\u01b0\u1ee3c 1 con s\u1ed1 l\u00e0 CD.<\/p>\n
Ta l\u1ea5y A + B = E; C + D = F. Nh\u01b0 v\u1eady ta c\u00f3 c\u1eb7p s\u1ed1 E v\u00e0 F.<\/p>\n
Ta s\u1ebd c\u00f3 c\u00e1c tr\u01b0\u1eddng h\u1ee3p sau:<\/p>\n
Tr\u01b0\u1eddng h\u1ee3p 1: N\u1ebfu E < 10 v\u00e0 F < 10 th\u00ec l\u1ea5y 10 \u2013 E = G v\u00e0 10 \u2013 F = H. Ta c\u00f3 l\u00f4 GH, HG \u0111\u1ec3 \u0111\u00e1nh cho ng\u00e0y ti\u1ebfp theo.<\/p>\n
Tr\u01b0\u1eddng h\u1ee3p 2: N\u1ebfu E < 10 v\u00e0 F > 10 th\u00ec l\u1ea5y 10 \u2013 E = G v\u00e0 20 \u2013 F = K. Ta c\u00f3 l\u00f4 GK, KG \u0111\u00e1nh cho ng\u00e0y ti\u1ebfp theo.<\/p>\n
Tr\u01b0\u1eddng h\u1ee3p 3: N\u1ebfu E > 10 v\u00e0 F < 10 th\u00ec l\u1ea5y 20 \u2013 E = T v\u00e0 10 \u2013 F = H. Ta c\u00f3 l\u00f4 TH, HT \u0111\u00e1nh cho ng\u00e0y ti\u1ebfp theo.<\/p>\n
Tr\u01b0\u1eddng h\u1ee3p 4: N\u1ebfu E > 10 v\u00e0 F > 10 th\u00ec l\u1ea5y 20 \u2013 E = T v\u00e0 20 \u2013 F = K. Ta c\u00f3 l\u00f4 TK, KT \u0111\u1ec3 \u0111\u00e1nh cho ng\u00e0y mai.<\/p>\n
N\u1ebfu tr\u01b0\u1eddng h\u1ee3p E, F \u0111\u1ec1u l\u00e0 0 th\u00ec \u0111\u00e1nh l\u00f4 k\u00e9p 00 cho ng\u00e0y h\u00f4m sau.<\/p>\n
V\u1edbi c\u00e1ch n\u00e0y ta n\u00ean nu\u00f4i t\u1ed1i \u0111a 3 ng\u00e0y. N\u1ebfu sau 3 ng\u00e0y kh\u00f4ng tr\u00fang th\u00ec \u0111\u1ee3i 3 ng\u00e0y n\u1eefa r\u1ed3i \u0111\u00e1nh \u0111\u00e1nh ti\u1ebfp<\/p>\n
Qua b\u00e0i vi\u1ebft n\u00e0y hy v\u1ecdng m\u1ecdi ng\u01b0\u1eddi s\u1ebd c\u00f3 c\u00e1i nh\u00ecn t\u1ed5ng qu\u00e1t h\u01a1n v\u1ec1 c\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t. \u0110\u00e2y l\u00e0 c\u00e1ch c\u00f3 hi\u1ec7u qu\u1ea3 th\u1ef1c ti\u1ec5n r\u1ea5t cao v\u00e0 \u0111\u1eb7c bi\u1ec7t khi \u00e1p d\u1ee5ng v\u1edbi b\u1ea1c nh\u1edb l\u00f4 \u0111\u1ec1 t\u1ea1o ra c\u1eb7p b\u00e0i tr\u00f9ng m\u00e0 ng\u01b0\u1eddi ch\u01a1i l\u00f4 \u0111\u1ec1 kh\u00f4ng n\u00ean b\u1ecf l\u1ee1.<\/p>\n