Trong b\u1ea5t k\u1ec3 m\u1ed9t lo\u1ea1i tr\u00f2 ch\u01a1i n\u00e0o c\u0169ng th\u1ebf, k\u1ec3 c\u1ea3 l\u00e0 l\u00f4 \u0111\u1ec1 c\u0169ng \u0111\u1ec1u c\u00f3 ph\u01b0\u01a1ng ph\u00e1p v\u00e0 c\u00e1ch ch\u01a1i ri\u00eang c\u1ee7a n\u00f3. V\u1eady mu\u1ed1n ch\u1ecdn s\u1ed1 \u0111\u1ec3 ch\u01a1i cho chu\u1ea9n ph\u1ea3i l\u00e0m sao? C\u00f9ng \u0111i t\u00ecm hi\u1ec3u th\u00eam nh\u00e9:<\/p>\n
C\u00e1ch ch\u1ecdn s\u1ed1:<\/h3>\n
1. Nh\u1eefng con lotto m\u00e0 h\u00f4m tr\u01b0\u1edbc v\u1ec1 \u0110B.
\n2. Nh\u1eefng con c\u00f3 t\u1ea7n su\u1ea5t v\u1ec1 cao, chu k\u1ef3 xu\u1ea5t hi\u1ec7n nh\u1ecf.
\n3. Nh\u1eefng con c\u00f3 th\u1ec3 s\u1eafp h\u1ebft chu k\u1ef3 gan 1 \u0111\u1ebfn 2 ng\u00e0y \u0111\u01b0\u1ee3c th\u1ed1ng k\u00ea trong kho\u1ea3ng 3 n\u0103m tr\u1edf l\u1ea1i, n\u00ean tr\u00e1nh nh\u1eefng con c\u00f3 chu k\u1ef3 gan qu\u00e1 nh\u1ecf( VD nh\u01b0 con 94).
\n4. Nh\u1eefng con v\u00f9a l\u00ean gan xong( qu\u00e1 12 ng\u00e0y).
\n5. Theo c\u1ea7u \u0111\u00e3 \u0111\u01b0\u1ee3c theo d\u00f5i khoang 2 n\u0103m tr\u1edf l\u00ean.
\nT\u00f9y t\u1eebng ho\u00e0n c\u1ea3nh c\u1ee5 th\u1ec3 m\u00e0 ta quy\u1ebft \u0111\u1ecbnh ch\u1ecdn s\u1ed1 n\u00e0o nh\u01b0ng h\u00e3y nh\u1edb l\u00e0 kh\u00f4ng n\u00ean n\u00f3ng v\u1ed9i v\u00ec b\u1ea1n v\u00e0o s\u1edbm 1 \u0111\u1ebfn 2 ng\u00e0y c\u00f3 \u0111\u01b0\u1ee3c th\u00ec c\u0169ng kh\u00f4ng \u0111\u01b0\u1ee3c nhi\u1ec1u nh\u01b0ng \u0111\u1ec3 r\u1ed3i n\u00f3 v\u1ec1 sau chu k\u1ef3 \u0111\u00e1nh 1 \u0111\u1ebfn 2 ng\u00e0y th\u00ec l\u1ea1i m\u1ea5t r\u1ea5t nhi\u1ec1u \u0111\u1ea5y.<\/p>\n
I. Nh\u1eefng con lotto m\u00e0 h\u00f4m tr\u01b0\u1edbc v\u1ec1 \u0110B.<\/h2>\n
Nh\u1eefng con v\u1ec1 \u0110B c\u00f3 t\u1ef7 l\u1ec7 v\u1ec1 l\u1ea1i trong 10 ng\u00e0y l\u00e0 kh\u00e1 cao, theo th\u1ed1ng k\u00ea c\u1ee7a m\u00ecnh l\u00e0 72%.<\/p>\n
II. Nh\u1eefng con c\u00f3 t\u1ea7n su\u1ea5t v\u1ec1 cao, chu k\u1ef3 xu\u1ea5t hi\u1ec7n nh\u1ecf.<\/h2>\n
<\/p>\n
C\u00e1c b\u1ea1n n\u00ean t\u1ef1 m\u00ecnh l\u00e0m ra m\u1ed9t b\u1ea3ng th\u1ed1ng k\u00ea \u0111\u1ec3 bi\u1ebft nh\u1eefng con s\u1ed1 n\u00e0o c\u00f3 t\u1ea7n su\u1ea5t \u0111\u1ec7p \u0111\u1ec3 t\u1eeb \u0111\u00f3 \u0111\u01b0a ra \u0111\u01b0\u1ee3c khung ng\u00e0y \u0111\u1ec3 \u0111\u00e1nh. V\u00ed d\u1ee5 m\u00ecnh th\u1ed1ng k\u00ea \u0111\u01b0\u1ee3c trong kho\u1ea3ng 2 n\u0103m tr\u1edf l\u1ea1i \u0111\u00e2y c\u00f3 4 con t\u1ea7n su\u1ea5t v\u1ec1 cao nh\u1ea5t l\u00e0 00, 22, 24 59. V\u1edbi nh\u1eefng con n\u00e0y th\u00ec sau kho\u1ea3ng 2 h\u00f4m n\u00f3 ch\u01b0a v\u1ec1 th\u00ec m\u00ecnh b\u1eaft \u0111\u1ea7u v\u00e0o.<\/p>\n
III. Nh\u1eefng con c\u00f3 th\u1ec3 s\u1eafp h\u1ebft chu k\u1ef3 gan 1 \u0111\u1ebfn 2 ng\u00e0y \u0111\u01b0\u1ee3c th\u1ed1ng k\u00ea trong kho\u1ea3ng 3 n\u0103m tr\u1edf l\u1ea1i, n\u00ean tr\u00e1nh nh\u1eefng con c\u00f3 chu k\u1ef3 gan qu\u00e1 nh\u1ecf( VD nh\u01b0 con 94).<\/h4>\nIV.Nh\u1eefng con v\u00f9a l\u00ean gan xong( qu\u00e1 12 ng\u00e0y)<\/h2>\n
Ph\u01b0\u01a1ng ph\u00e1p n\u00e0y th\u01b0o m\u00ecnh c\u00f3 t\u1ef7 l\u1ec7 cao nh\u1ea5t( 90%)
\nC\u00e1c b\u1ea1n n\u1ebfu \u0111\u00e3 th\u1ed1ng k\u00ea th\u00ec th\u1ea5y trong kho\u1ea3ng th\u1eddi gian c\u00e0ng l\u00e2u th\u00ec kh\u1ecfng c\u00e1ch v\u1ec1 c\u1ee7a c\u00e1c con s\u1ed1 c\u00e0ng thu l\u1ea1i. Nh\u00ecn chung th\u00ec nh\u1eefng con n\u00e0o v\u1eeba l\u00ean gan xong th\u00ec s\u1ebd v\u1ec1 nhi\u1ec1u sau \u0111\u00f3 nh\u01b0ng c\u0169ng c\u00f3 nh\u1eefng tr\u01b0\u1eddng h\u1ee3p l\u00ean gan li\u00ean ti\u1ebfp( 58), nh\u1eefng con n\u00e0y th\u01b0\u1eddng n\u1eb1m \u1edf top cu\u1ed1i c\u1ee7a b\u1ea3ng th\u1ed1ng k\u00ea v\u00ec v\u1eady c\u00e1c b\u1ea1n n\u00ean c\u1ea9n th\u1eadn.<\/p>\n
V.C\u1ea7u.<\/h2>\n
V\u1ec1 c\u1ea7u th\u00ec m\u00ecnh ch\u1eafc nh\u1eefng ai \u0111\u00e1nh lotto l\u00e2u r\u1ed3i th\u00ec \u0111\u1ec1u c\u00f3 nh\u1eefng c\u1ea7u ru\u1ed9t c\u1ee7a m\u00ecnh. \u1ede \u0111\u00e2y m\u00ecnh xin \u0111\u01b0a ra m\u1ea5y c\u1ea7u m\u00ecnh \u0111\u00e3 ki\u1ec3m tra l\u00e2u r\u1ed3i \u0111\u1ec3 m\u1ecdi ng\u01b0\u1eddi tham kh\u1ea3o. Ai c\u00f3 nh\u1eadn x\u00e9t g\u00ec xin h\u00e3y \u0111\u01b0a l\u00ean \u0111\u1ec3 m\u1ecdi ng\u01b0\u1eddi c\u00f9ng tham kh\u1ea3o.<\/p>\n
1. T\u1ed5ng gi\u1ea3i \u0110B ng\u00e0y th\u1eeb 7 s\u1ebd v\u1ec1 trong 7 ng\u00e0y.
\nC\u00e1i n\u00e0y \u0111\u00e3 test trong 2 n\u0103m
\n2. T\u1ed5ng gi\u1ea3i nh\u1ea5t ng\u00e0y th\u1ee9 5 s\u1ebd v\u1ec1 trong 8 ng\u00e0y.
\nC\u00e1i n\u00e0y \u0111\u00e3 test trong 2 n\u0103m.
\n3. C\u1ea7u \u0111\u00e1nh c\u1eb7p.
\n\u2013 T\u1ed5ng s\u1ed1 th\u1ee9 1 v\u00e0 th\u1ee9 3 c\u1ee7a gi\u1ea3i 7
\n\u2013 T\u1ed5ng s\u1ed1 2 v\u00e0 th\u1ee9 4 c\u1ee7a gi\u1ea3i 7
\nC\u00e1c c\u1eb7p n\u00e0y s\u1ebd v\u1ec1 trong 7 ng\u00e0y, C\u00e1i n\u00e0y \u0111\u00e3 test trong 1 n\u0103m.<\/p>\n
\u0110\u1ec3 gi\u00fap c\u00e1c b\u1ea1n d\u1ec5 hi\u1ec3u h\u01a1n t\u1eeb gi\u1edd m\u00ecnh s\u1ebd update c\u00e1c con s\u1ed1 l\u00ean h\u00e0ng ng\u00e0y.
\nNg\u00e0y 21\/9 20, 29 \u0111\u00e3 v\u1ec1.
\n36 \u0111\u00e3 t\u1eed tr\u1eadn. C\u00e1 nh\u00e2n m\u00ecnh c\u0169ng m\u1ea5t nhi\u1ec1u v\u00ec em n\u00e0y nh\u01b0ng may c\u00f3 nh\u1eefng em kh\u00e1c b\u00f9 l\u1ea1i.
\nNg\u00e0y 22\/9 424, 797 khung 5 ng\u00e0y.
\n24 khung 6 ng\u00e0y.<\/p>\n
<\/p>\n
Ph\u01b0\u01a1ng ph\u00e1p:<\/h3>\n
C\u00e1c b\u1ea1n \u0111\u00e3 v\u00e0 \u0111ang h\u00e0ng ng\u00e0y t\u00ecm ra 27 con s\u1ed1 trong 100 con s\u1ed1 nh\u01b0ng b\u00e2y gi\u1edd c\u00e1c b\u1ea1n h\u00e3y l\u00e0m ng\u01b0\u1ee3c l\u1ea1i l\u00e0 t\u00ecm ra 73 con s\u1ed1, m\u00ecnh ngh\u0129 ch\u1eafc s\u1ebd d\u1ec5 h\u01a1n v\u00ec t\u1ef7 l\u1ec7 b\u00e2y gi\u1edd cao h\u01a1n nhi\u1ec1u r\u1ed3i.<\/p>\n
M\u00ecnh xin n\u00eau VD c\u1ee5 th\u1ec3 nh\u01b0 sau:
\nB\u00ecnh th\u01b0\u1eddng m\u00ecnh \u0111\u00e1nh lotto l\u00e0 22k\/1\u0111.
\nN\u1ebfu \u0111\u00e1nh c\u1ea3 100 con m\u1ed7i con 1 \u0111i\u1ec3m th\u00ec m\u00ecnh thu v\u1ec1 80\/22\u00d727=98,1818\u0111.
\nV\u1eady m\u00ecnh l\u1ed7 l\u00e0 100 \u2013 98,1818 = 1,8182\u0111.
\n\u0110\u1ea5y l\u00e0 n\u1ebfu m\u00ecnh \u0111\u00e1nh 100 con c\u00f2n n\u1ebfu m\u00ecnh \u0111\u00e1nh d\u01b0\u1edbi 98 con m\u00e0 v\u1eabn v\u1ec1 h\u1ebft 27 con th\u00ec m\u00ecnh \u0111\u00e3 c\u00f3 l\u00e3i( l\u00e3i nhi\u1ec1u hay \u00edt l\u00e0 t\u00f9y v\u00e0o c\u00e1c b\u1ea1n).<\/p>\n
V\u1eady n\u1ebfu m\u1ed9t ng\u00e0y ch\u1ec9 c\u1ea7n b\u1ea1n lo\u1ea1i chu\u1ea9n 2 con l\u00e0 b\u1ea1n \u0111\u00e3 c\u00f3 l\u00e3i r\u1ed3i, \u0111i\u1ec1u n\u00e0y v\u1edbi m\u1ed9t s\u1ed1 ng\u01b0\u1eddi ch\u01a1i l\u00e2u c\u00f3 nghi\u00ean c\u1ee9u th\u00ec m\u00ecnh ngh\u0129 l\u00e0 chuy\u1ec7n kh\u00f4ng kh\u00f3 t\u00fd n\u00e0o.
\nT\u1ef7 l\u1ec7 c\u1ee7a 1 con tr\u00fang = 80\/22 = 3,6363 con \u0111\u00e1nh n\u00ean b\u1ea1n c\u00e0ng lo\u1ea1i nhi\u1ec1u v\u00e0 chu\u1ea9n bao nhi\u00eau th\u00ec cang \u0111\u01b0\u1ee3c b\u1ea5y nhi\u00eau.<\/p>\n
V\u1edbi m\u00ecnh hi\u1ec7n t\u1ea1i m\u00ecnh \u0111\u00e1nh m\u1ed7i con 5\u0111, 1 ng\u00e0y lo\u1ea1i kho\u1ea3ng 12 con. N\u1ebfu chu\u1ea9n h\u1ebft th\u00ec \u0111\u01b0\u1ee3c 5\u00d710 = 50 x 22k = 1,1t 1 ng\u00e0y.
\nC\u00e1ch lo\u1ea1i s\u1ed1 c\u1ee7a m\u00ecnh l\u00e0:
\n+ Lo\u1ea1i nh\u1eefng con v\u1ec1 2 ng\u00e0y li\u00ean ti\u1ebfp tr\u1edf l\u00ean.
\n+ Lo\u1ea1i nh\u1eefng con s\u1eafp ho\u1eb7c \u0111ang l\u00ean gan( theo kinh nghi\u1ec7m).<\/p>\n
Tr\u00ean \u0111\u00e2y l\u00e0 ph\u01b0\u01a1ng ph\u00e1p v\u00e0 kinh nghi\u1ec7m kh\u00e1 hay, mong c\u00e1c b\u1ea1n c\u00f9ng m\u00ecnh g\u00f3p s\u1ee9c x\u00e2y d\u1ef1ng \u0111\u1ec3 ph\u01b0\u01a1ng ph\u00e1p n\u00e0y c\u00f3 t\u1ef7 l\u1ec7 th\u00e0nh c\u00f4ng cao h\u01a1n n\u1eefa. N\u1ebfu m\u1ecdi ng\u01b0\u1eddi \u0111\u1ed3ng l\u00f2ng chung nhau g\u00f3p s\u1ee9c th\u00ec m\u00ecnh ngh\u0129 ph\u01b0\u01a1ng ph\u00e1p n\u00e0y s\u1ebd c\u00f3 t\u00ednh kh\u1ea3 thi 100% \u0111\u1ea5y, ngh\u0129a l\u00e0 ng\u00e0y n\u00e0o ta c\u0169ng c\u00f3 ti\u1ec1n.<\/p>\n<\/div>\n<\/div>\n<\/div>\n